Social: which platforms this run has

Inputs

Outputs

Source

python

# Input preparation
inp = __ivy_ctx__["nodes"][__ivy_node_id__]["input"]

# Compute
# Shared by every social node (built into each by build.mjs): dates, blocks, merging.
import datetime, json, re, statistics

def day(s):
    s = str(s or "")[:10]
    return s if re.fullmatch(r"\d{4}-\d{2}-\d{2}", s) else None

def now_iso():
    return datetime.datetime.utcnow().replace(microsecond=0).isoformat() + "Z"

def ms_of(s):
    if s is None or s == "":
        return None
    if isinstance(s, (int, float)):
        return int(s * 1000) if s < 1e12 else int(s)
    t = str(s).replace("Z", "+00:00")
    t = re.sub(r"([+-]\d{2})(\d{2})$", r"\1:\2", t)
    try:
        return int(datetime.datetime.fromisoformat(t).timestamp() * 1000)
    except ValueError:
        return None

def rows_of(block):
    """A {fields, rows} block as dicts."""
    if not isinstance(block, dict) or not block.get("fields"):
        return []
    f = block["fields"]
    return [dict(zip(f, r)) for r in block.get("rows") or []]

def block_of(dicts, first):
    fields = list(first)
    for d in dicts:
        for k in d:
            if k not in fields:
                fields.append(k)
    return {"fields": fields, "rows": [[d.get(k) for k in fields] for d in dicts]}

def listed(v):
    return [x for x in (v if isinstance(v, list) else [v] if v else []) if x is not None]

def text_of(v, limit=4000):
    s = " ".join(str(v).split()) if isinstance(v, (str, int, float)) else ""
    return s[:limit]


class SocialPlan:
    "Social: which platforms this run has"

    def run(self, inp):
        out = {}
        # Which platforms this run has: a connection and an id per platform, so the agent's if-branches skip the rest.
        def has(conn, *ids):
            return bool(inp.get(conn)) and all(bool(inp.get(i)) for i in ids)
        out["has_instagram"] = has("ig_connection", "ig_user_id")
        out["has_facebook"] = has("fb_connection")
        out["has_linkedin"] = has("li_connection", "li_organization_id")
        out["has_x"] = has("x_connection")
        out["has_youtube"] = has("yt_connection")
        out["platforms"] = [p for p, ok in (("instagram", out["has_instagram"]), ("facebook", out["has_facebook"]), ("linkedin", out["has_linkedin"]), ("x", out["has_x"]), ("youtube", out["has_youtube"])) if ok]
        out["count"] = len(out["platforms"])
        out["client"] = inp.get("client") or ""
        out["days"] = int(inp.get("days") or 7)
        return out


result = SocialPlan().run(inp)

# Output collection (the runner reads it here)
out = __ivy_ctx__["nodes"][__ivy_node_id__]["output"]
out.update(result)

Tests

Requires: python:3.9

• two

  Instagram with its id and X are there; LinkedIn is not, so its branch is skipped.

• none

  An empty input has no platform and reads seven days.

• id-missing

  A LinkedIn connection without the company page's id is not a platform this run can read.